Divisibility Test (Division
Rules in Maths)
Divisibility tests |
Divisibility by 1
Every number is divisible by
1. Divisibility rule for 1 doesn’t have any particular condition. .
Divisibility by 2
All even numbers or any
number whose last digit is an even number i.e.
2,4,6,8 including 0 is always exactly divisible by 2.
Divisibility Rules for 3
Divisibility rule for 3
states that a number is exactly divisible by 3 if the sum of its digits is
divisible by 3 i.e., it is a multiple of 3
Divisibility by 4
If the last two digits of a
number are divisible by 4, then that number is a multiple of 4 and is divisible
by 4 exactly.
Divisibility by 5
Numbers with last digit 0 or
5 are always divisible by 5.
Divisibility by 6
Numbers which are divisible
by both 2 and 3 are divisible by 6. That is, if last digit of the given number
is even and the sum of its digits is a multiple of 3, then the given number is
also a multiple of 6 and exactly divisible by 8.
Divisibility Rules for 7
The rule for divisibility by
7 is given below:
Double the last digit and
subtract it from the remaining leading truncated number. If the result is
divisible by 7, then so was the original number. Apply this rule over and over
again as necessary. Example: 826. Twice 6 is 12. So take 12 from the truncated
82. Now 82-12=70. This is divisible by 7, so 826 is divisible by 7 also.
Divisibility by 8
If the last three digits of
a number are divisible by 8, then the number is exactly divisible by 8.
Divisibility by 9
The rule for divisibility by
9 is similar to divisibility rule for 3. That is, if the sum of digits of the
number is divisible by 9, then the number itself is divisible by 9.
Divisibility by 10
The rule for divisibility by
10 is that for any number whose last digit is 0, it is divisible by 10.
Divisibility Rules for 11
If the difference of the sum
of alternative digits of a number is divisible by 11 or zero then that number
is divisible by 11 completely.
In order to check whether a
number like 11121 is divisible by 11 following is the procedure.
Group the alternative digits i.e. digits
which are in odd places together and digits in even places together. Here 111
and 12 are two groups.
Take the sum of the digits of each group
i.e. 1+1+1=3 and 1+2= 3
Now find the difference of the sums; 3-3=0
If the difference is zero / divisible by
11, then the original number is also divisible by 11. Here 0 is the difference.
Therefore, 11121 is divisible by 11.
In order to check whether a
number like 7145 is divisible by 11 following is the procedure.
Group the alternative digits
i.e. digits which are in odd places together and digits in even places
together. Here 74 and 15 are two groups.
Take the sum of the digits
of each group i.e. 7+4=11 and 1+5= 6
Now find the difference of the sums; 11-6=5
If the difference is divisible by 11, then the
original number is also divisible by 11. Here 5 is the difference which is not
divisible by 11.
Therefore, 7145 is not divisible by 11.
Divisibility by 12
If a number is divisible by both 3 and 4, then it is divisible by 12.
Divisibility by 12
If a number is divisible by both 3 and 4, then it is divisible by 12.
Divisibility Rules for 13
Test for divisibility by 13.
Add four times the last digit to the remaining leading truncated number. If the
result is divisible by 13, then so was the first number. Apply this rule over
and over again as necessary.
Example: 50661 =>5066+4=5070
=>507+0=507
=>50+28=78
and 78 is a multiple of 13 (i.e., 78= 6x13), so 50661 is divisible by 13.
Divisibility by 15
If a number is divisible by both 3 and 5, then it is divisible by 15.
Divisibility by 18
If a number is divisible by both 2 and 9, then it is divisible by 18.
Divisibility by 25
In a number, if the last two digits are zeroes or the number formed by the last two digits is a multiple of 25, then the number is divisible by 25.
Divisibility by 15
If a number is divisible by both 3 and 5, then it is divisible by 15.
Divisibility by 18
If a number is divisible by both 2 and 9, then it is divisible by 18.
Divisibility by 25
In a number, if the last two digits are zeroes or the number formed by the last two digits is a multiple of 25, then the number is divisible by 25.